The Mirrored Road into the Interior

So Cold. My own fault, but still...
On the up side I got the hash browns I wanted today, broke down and went to burger king. On the down side? I forgot they used croissants, so I got the wrong sandwich to go with them. And I had some diet coke. This is, by the way, why I am cold. I pretty much don't drink anything without ice any more (except soda from a can.) I had 3 32 oz diet cokes, so I had about 32 oz of ice and 64 oz of cold liquid. Assuming that the Diet Coke is pretty close to plain water.

By the way, the numbers below are approximations and estimates, not the real thing. In other words this is just a back of the envelope calculation based on poor input data.

Let's say that the ice is held at 5 degrees below freezing. No idea if that is correct, but it seems reasonable.
Also, since it was hard ice, the coke wasn't a coke/ice slurry, so we'll say it was 5 degrees above freezing.

Also assume that my body self regulates to 37 degrees.

Specific heat of ice in cal/g is .5, water is 1.0

Latent heat of water is approximately 80 cal/g going from solid to liquid.

32 oz is about 946 ml so I had approximately 1892 grams of diet coke and 851 g of ice (ice is .9 g/ml)

Heating the water to 37 degrees will run about 32 cal per gram or 60,544 cal. Heating the Ice to 0 degrees costs 2.5 cal per gram or 2127.5 cal. melting it at zero costs 80 cal/g or 68080 cal (notice it takes more heat to melt ice without changing the ice's temperature than it does to heat more than twice as much water 32 degrees.) then we have to heat that ice 37 degrees at a cost of 37 cal/gram or 31487 cal. Grand total? about 162,000 calories. (little c)

That is enough to drop a blob of water the mass of an average adult human male 2.3 degrees. Of course I weigh a great deal more than the average adult human male, but it is still quite a hit on my core temperature (and it isn't applied evenly across my body, having originally hit the center bits of my body, thus convincing my body to reduce blood flow to the extremities until the big old chunk of cold is passed. (Notice that unless the ice was extremely cold, the ice's starting temperature was not particularly important. With my assumptions, it comes out to 1.3 percent of the total heat needed to warm it back up. This is way less than the margin of error on my assumptions.)

Long number story short? I'm cold and it is my own damned fool fault.